[signal] Serialize concurrent sends to a peer signal stream (#6463)

This commit is contained in:
Viktor Liu
2026-06-18 22:00:19 +09:00
committed by GitHub
parent ee360963f9
commit d3710d4bb2
3 changed files with 79 additions and 1 deletions

View File

@@ -26,6 +26,10 @@ type Peer struct {
// a gRpc connection stream to the Peer
Stream proto.SignalExchange_ConnectStreamServer
// sendMu serializes writes to Stream. gRPC forbids concurrent SendMsg on
// the same ServerStream, and a peer can be the target of many senders at
// once.
sendMu sync.Mutex
// registration time
RegisteredAt time.Time
@@ -33,6 +37,13 @@ type Peer struct {
Cancel context.CancelFunc
}
// Send writes a message to the peer's stream, serializing concurrent senders.
func (p *Peer) Send(msg *proto.EncryptedMessage) error {
p.sendMu.Lock()
defer p.sendMu.Unlock()
return p.Stream.Send(msg)
}
// NewPeer creates a new instance of a connected Peer
func NewPeer(id string, stream proto.SignalExchange_ConnectStreamServer, cancel context.CancelFunc) *Peer {
return &Peer{

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@@ -0,0 +1,67 @@
package server
import (
"context"
"sync"
"sync/atomic"
"testing"
"time"
"github.com/stretchr/testify/require"
"go.opentelemetry.io/otel"
"github.com/netbirdio/netbird/shared/signal/proto"
"github.com/netbirdio/netbird/signal/peer"
)
// concurrencyCheckStream records the maximum number of Send calls in flight at
// once. gRPC forbids concurrent SendMsg on the same ServerStream, so a correct
// server must never have more than one in flight per peer.
type concurrencyCheckStream struct {
proto.SignalExchange_ConnectStreamServer
ctx context.Context
inflight atomic.Int32
maxSeen atomic.Int32
}
func (s *concurrencyCheckStream) Send(*proto.EncryptedMessage) error {
n := s.inflight.Add(1)
for {
old := s.maxSeen.Load()
if n <= old || s.maxSeen.CompareAndSwap(old, n) {
break
}
}
// Widen the window so overlapping callers are reliably observed.
time.Sleep(time.Millisecond)
s.inflight.Add(-1)
return nil
}
func (s *concurrencyCheckStream) Context() context.Context { return s.ctx }
// TestForwardMessageToPeerSerializesSend verifies that concurrent forwards to the
// same peer never call Stream.Send concurrently, which would violate the gRPC
// ServerStream contract.
func TestForwardMessageToPeerSerializesSend(t *testing.T) {
s, err := NewServer(context.Background(), otel.Meter(""))
require.NoError(t, err)
const peerID = "peerX"
stream := &concurrencyCheckStream{ctx: context.Background()}
_, cancel := context.WithCancel(context.Background())
t.Cleanup(cancel)
require.NoError(t, s.registry.Register(peer.NewPeer(peerID, stream, cancel)))
var wg sync.WaitGroup
for i := 0; i < 50; i++ {
wg.Add(1)
go func() {
defer wg.Done()
s.forwardMessageToPeer(context.Background(), &proto.EncryptedMessage{Key: "sender", RemoteKey: peerID})
}()
}
wg.Wait()
require.Equal(t, int32(1), stream.maxSeen.Load(), "Stream.Send must never run concurrently on the same peer stream")
}

View File

@@ -179,7 +179,7 @@ func (s *Server) forwardMessageToPeer(ctx context.Context, msg *proto.EncryptedM
sendResultChan := make(chan error, 1)
go func() {
select {
case sendResultChan <- dstPeer.Stream.Send(msg):
case sendResultChan <- dstPeer.Send(msg):
return
case <-dstPeer.Stream.Context().Done():
return